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Question

The angular momentum of an electron in 3d orbital is:

A
2hπ
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B
5hπ
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C
3h2π
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D
6h2π
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Solution

The correct option is D 6h2π
Angular momentum of an electron in an orbital =(l+1)h2π

For d orbital, l=2

Angular momentum=2(2+1)h2π=6h2π


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