Question

The angular momentum of an electron in a orbital is given as ______.

• A. $\sqrt{l(l-1)}$(h/2$pi$)
• B. $\sqrt{l(l+1)}$(h/2$pi$)
• C. $\sqrt{(l+1)}$(h/2$pi$)
• D. $\sqrt{l(l+2)}$(h/2$pi$)

Answer 1

The correct option is B $\sqrt{l(l+1)}$(h/2$pi$)

Angular momentum in an orbital = $\frac{h}{2\pi }\sqrt{l(l+1)}$

$l=0$ for s orbital angular momentum =$0$

$l=1$ for p orbital

$\therefore$ Angular momentum = $\frac{h}{2\pi }\sqrt{(1+1)\times 1}=\frac{h}{\sqrt{2\pi }}$