The angular momentum of electron in $n^{t h}$ orbit is given by

n h

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\frac{h}{2 π n}

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n \frac{h}{2 π}

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n^{2} \frac{h}{2 π}

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Solution

The correct option is C $n \frac{h}{2 π}$
According to Bohr's second postulate, angular momentum is integral multiple of $\frac{h}{2 π}$ .
So, $m v r = n (\frac{h}{2 π})$

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