Question

The angular speed of a motor increases from $600to1200rpm$ in $10s$. What is the angular acceleration of the motor?

• A. $60rad/s^2$
• B. $2\pi rad/s^2$
• C. $60\pi rad/s^2$
• D. $600rad/s^2$

Answer 1

The correct option is B $2\pi rad/s^2$

$1rpm$=$\frac{\pi }{30}$$rad/s$

$\alpha =\frac{\Delta \omega }{\Delta t}=\frac{\frac{\pi }{30}(1200-600)}{10}=\frac{\frac{\pi }{30}\left(600\right)}{10}=2\pi$ $rad/s^2$