Question

# The angular velocity of a particle is given by ω=1.5t−3t2+2, the time when its angular acceleration ceases to exist will be -

A
25 sec
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B
0.25 sec
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C
12 sec
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D
1.2 sec
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Solution

## The correct option is B 0.25 secIt is given that ω=1.5t−3t2+2, we know that angular acceleration refers to time rate of change of angular velocity α=dωdt=1.5−6t When the angular acceleration becomes zero, α=0 we get, ⇒α=1.5−6t=0 ⇒t=1.56=0.25 sec Hence correct answer is (b)

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