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B
2.1
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C
2.01
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D
none of these
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Solution
The correct option is B 2.0125 (33)1/5=(32+1)1/5 Let y=f(x)=x1/5 ⇒y+Δy=(x+Δx)1/5 ⇒Δy=(x+Δx)1/5−x1/5 Also, Δy=f′(x)Δx ⇒(x+Δx)1/5−x1/5=15x−4/5Δx Put x=32,Δx=1 (33)1/5−(32)1/5=15(2)−4(1) ⇒(33)1/5=2+0.0125=2.0125