Question

The approximate wavelength of a photon of energy 2.48 eV is

• A. $500\dot{A}$
• B. $5000\dot{A}$
• C. $2000\dot{A}$
• D. $1000\dot{A}$

Answer 1

The correct option is B $5000\dot{A}$

By using $E\left(eV\right)=\frac{12375}{\lambda \left(\dot{(}A\right))}$
$\Rightarrow \lambda =\frac{12375}{2.48}=4989.9\dot{A}\approx 5000\dot{A}$