Question

The area $\left(inc{m}^2\right)$ of a sector of a circle with an angle of ${45}^o$ and radius $3$ cm is_.

• A. $3\frac{13}{14}$
• B. $4\frac{13}{14}$
• C. $3\frac{51}{56}$
• D. $3\frac{15}{28}$

Answer 1

The correct option is D $3\frac{15}{28}$

Given circle radius $=3cm$ (r)

Sector angle $=45$

Area of sector $=\frac{45}{360}\times \pi r^2$

$=\frac{1}{8}\times \frac{22}{7}\times (3{)}^2$

$=\frac{22}{8.7}\times 9$

$=\frac{99}{28}$ sq. cm

$=3\frac{15}{28}$ sq. cm.