The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

True

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False

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Solution

The correct option is B
False

Area of the sector of angle $θ$ = $\frac{θ}{360}$ × $π r^{2}$

A = $\frac{60}{360}$ × $π (6^{2})$ = 18.85 $c m^{2}$

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Similar questions

State true or false.
The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is ___ $c m^{2}$ .

The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is _________

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ $c m^{2}$ . ( Take $π$ = $\frac{22}{7}$ )

Q. Find the area of a sector of a circle with radius

6 c m

if angle of the sector is

60^{\circ} .

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The area in cm2 of a sector of a circle with radius 6 cm and angle of the sector 60∘ is 20.

The correct option is B False Area of the sector of angle θ = θ360 × πr2 A = 60360 × π (62) = 18.85 cm2

The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

The correct option is B
False

Area of the sector of angle $θ$ = $\frac{θ}{360}$ × $π r^{2}$

A = $\frac{60}{360}$ × $π (6^{2})$ = 18.85 $c m^{2}$