The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is ___ $c m^{2}$ .

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Solution

Area of the sector of angle $θ$ = $\frac{θ}{360}$ × $π$ $r^{2}$

Area = $\frac{60}{360}$ × $π$ × $6^{2}$ = 18.85 $c m^{2}$

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The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is _________

The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

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State true or false.
The area in $c m^{2}$ of a sector of a circle with radius 6 cm and angle of the sector $60^{\circ}$ is 20.

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . ( Take $π$ = $\frac{22}{7}$ )

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The area in cm2 of a sector of a circle with radius 6 cm if angle of the sector is 60∘ is ___ cm2.

Area of the sector of angle θ= θ360 × π r2 Area = 60360 × π× 62 = 18.85 cm2

The area in $c m^{2}$ of a sector of a circle with radius 6 cm if angle of the sector is $60^{\circ}$ is ___ $c m^{2}$ .

Area of the sector of angle $θ$ = $\frac{θ}{360}$ × $π$ $r^{2}$

Area = $\frac{60}{360}$ × $π$ × $6^{2}$ = 18.85 $c m^{2}$