Question

The area of a hole of heat furnace is ${10}^{-4}{m}^2$. It radiates $1.58\times {10}^{5}cal$ of heat per hour. If the emissivity of the furnace is $0.80$, then its temperature is

• A. $1500K$
• B. $2000K$
• C. $2500K$
• D. $3000K$

Answer 1

The correct option is B $2000K$

Since,the energy is given by $E=\sigma eA{T}^4$

$1.58\times {10}^{5}Calperhour=5.67\times {10}^{-8}0.80\times {10}^{-}4m^2\times T^4$

On solving above we have T=2000K