Question

The area of a parallelogram is $70d{m}^2$ and its attitude is 7 dm then the perimeter of a rectangle of equal area standing on the same base is

• A. 40 dm
• B. 28 dm
• C. 34 dm
• D. 17 dm

Answer 1

The correct option is C 34 dm

Given the area of parallelogram is 70 sq dm and altitude is 7 dm

Then Area of parallelogram=$a\times 7=70\Rightarrow a=10$ ( a is the side of parallelogram

The area of rectangle whose base is same and area is equal to parallelogram

$\therefore 10\times h=70\Rightarrow h=7$ dm

So perimeter =2(10+7)=34 dm