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Question

The area of a rectangle is 25a2−35a+12. If the length is given as 5a−3, then the width is .

A
4a5
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B
a4
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C
5a4
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D
5a3
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Solution

The correct option is C 5a4
Let y be the width.

Since area is given as 25a235a+12 which is the product of y and (5a3), we have
y(5a3)=25a235a+12.

To find y, we need to divide 25a235a+12 by 5a3.
5a45a325a235a+12 25a215a –––––––––––––––2 20a+12 20a+12–––––––––– 0y=5a4.

Hence, the width of the rectangle is (5a4).

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