Question

The area of a rectangle is $25a^2-35a+12$. If the length is given as $5a-3$, then the width is .

• A. $4a-5$
• B. $a-4$
• C. $5a-4$
• D. $5a-3$

Answer 1

The correct option is C $5a-4$

Let $y$ be the width.

Since area is given as $25a^2-35a+12$ which is the product of $y$ and $(5a-3),$ we have
$y(5a-3)=25a^2-35a+12.$

To find y, we need to divide $25a^2–35a+12$ by $5a-3.$
$$\begin{array}{c}5a-4\\ 5a-325a^2-35a+12\\ \underset{–}{25a^2-15a}2\\ -20a+12\\ \underset{–}{-20a+12}\\ 0\end{array}$$$\therefore y=5a-4$.

Hence, the width of the rectangle is $(5a-4)$.