Question

The area of a rectangle is 540 cm² and its length is 36 cm. Find its width and perimeter.

Answer 1

Let the width of the rectangle be x cm.
Length of the rectangle = 36 cm
Area of the rectangle = ($\mathrm{Length}\times \mathrm{Width}$) = ($36\times \mathrm{x}$) cm²
It is given that the area of the rectangle is 540 cm².

$$\begin{gathered} \Rightarrow 36\times x=540 \\ \Rightarrow x=\frac{540}{36} \\ \Rightarrow x=15 \\ \therefore W\mathrm{idth}\mathrm{of}\mathrm{the}\mathrm{rectangle}=15\mathrm{cm} \end{gathered}$$

Perimeter of the rectangle = 2(Length + Width) cm
= 2(36 + 15) cm
= 102 cm