The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle)
A
nR22sin(2πn)
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B
nr2tan(πn)
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C
na24cotπn
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D
nR2tan(πn)
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Solution
The correct options are AnR22sin(2πn) Bnr2tan(πn) Cna24cotπn Area of the regular polygon will be =nR22sin(2πn). Now R=s2sin(πn) Hence A=ns28sin2πn.2sin(πn).cos(πn) =ns24.cot(πn). where s is the side of the polygon. =nr2.tan(πn) where r is the incentre.