Question

The area of a rhombus is 216 sq. cm. If its one diagonal is 24 cm; find :
(i) length of its other diagonal,
(ii) length of its side,
(iii) perimeter of the rhombus.

Answer 1

Area of rhombus = $\frac{1}{2}\times D_1\times D_2$

$216=\frac{1}{2}\times 24\times D_2$

(1) $D_2=\frac{216}{12}=18$

(2) Diagonals perpendicular bisector of each other

$OA=DC=12$ & $DB=OD=9$

$A{B}^2={12}^2+9^2=144+81=225$

$AB=15cm$

(3) perimeter $=4x15=60cm$