The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . $T a k e π = \frac{22}{7}$

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Solution

The correct option is B 22
Given that radius $r = 6 c m$
$θ = 70^{\circ}$
Area of sector of an angle $θ$ with radius r,
$A = \frac{70}{360} \times \frac{22}{7} \times 6^{2}$
$= 22 c m^{2}$

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The area of a sector (in cm2 )of a circle with radius 6 cm if angle of the sector is 70∘ will be __ . Take π=227

The correct option is B 22Given that radius r=6 cm θ=70∘ Area of sector of an angle θ with radius r, A=70360×227×62 =22cm2

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . $T a k e π = \frac{22}{7}$

The correct option is B 22
Given that radius $r = 6 c m$
$θ = 70^{\circ}$
Area of sector of an angle $θ$ with radius r,
$A = \frac{70}{360} \times \frac{22}{7} \times 6^{2}$
$= 22 c m^{2}$