The area of a trapezium is 405 $c m^{2}$ . Its parallel sides are in the ratio 4 : 5 and the distance between them is 18 cm. Find the length of each of the parallel sides.

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Solution

$Area of trapezium = 405 m^{2} Ratio in paralle sides =4:5 and distance between them =18 cm ∴ Sum of parallel sides = \frac{A r e a \times 2}{A l t i t u d e} = \frac{405 \times 2}{18} = 45 m Let first paralles sides =4x Then second side =5x ∴ 4 x + 5 x = 45 \Rightarrow 9 x = 45 \Rightarrow x = \frac{45}{9} = 5 ∴ First parallel side = 4 x = 4 \times 5 = 20 c m and second side = 5 x = 5 \times 5 = 25 c m$

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The area of a trapezium is 405 cm2. Its parallel sides are in the ratio 4 : 5 and the distance between them is 18 cm. Find the length of each of the parallel sides.

Area of trapezium =405m2Ratio in paralle sides =4:5and distance between them =18 cm∴Sum of parallel sides=Area×2Altitude=405×218=45 mLet first paralles sides =4xThen second side =5x∴4x+5x=45⇒9x=45⇒x=459=5∴First parallel side =4x=4×5=20 cmand second side =5x=5×5=25 cm

The area of a trapezium is 405 $c m^{2}$ . Its parallel sides are in the ratio 4 : 5 and the distance between them is 18 cm. Find the length of each of the parallel sides.