The area of base of a cylinder vessel is 300cm2. Water (density = 1000kgm−3) is poured into it up to a depth of 6cm. (g=10ms−2).Then find the pressure and thrust on the base.
A
the pressure=600Pa
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B
thrust of water on the base=18N
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C
thrust of water on the base=36N
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D
the pressure=1200Pa
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Solution
The correct options are A the pressure=600Pa D thrust of water on the base=18N
(a) We, know that Pressure =ρ×g×h
where, ρ= density =1000kgm−3
g= acceleration due to gravity =10ms−2
h=height=6cm=0.06m
So, pressure =1000×0.06×10=600Pa
(b) Upthrust = Force exerted = Pressure \times Area