Question

the area of cross section of the pump plunger and press plunger of a hydraulic press are 0.02 m² and 8 m² .if the hydraulic press overcomes a load of 800 kgf calculate the force acting on pump plunger . if the mechanical advantage of the handle of pump plunger is 8 calculate the force applied at the end of the handle of pump plunger

Answer 1

$$\begin{gathered} \frac{\mathrm{Load}}{\mathrm{Effort}}=\frac{\mathrm{Press}\mathrm{plunger}\mathrm{cross}-\mathrm{sectional}\mathrm{area}}{\mathrm{pimp}\mathrm{plunger}\mathrm{cross}-\mathrm{sectional}\mathrm{area}} \\ \frac{800}{\mathrm{E}}=\frac{8}{0.02} \\ \mathrm{Hence}, \\ \mathrm{Effort}\mathrm{applied}\mathrm{on}\mathrm{the}\mathrm{pump}\mathrm{plunger}=\frac{800\times 0.02}{8} \\ =2\mathrm{kgf} \\ \mathrm{Effort}\mathrm{applied}\mathrm{at}\mathrm{the}\mathrm{end}\mathrm{of}\mathrm{the}\mathrm{handle}=\frac{\mathrm{Effort}\mathrm{applied}\mathrm{on}\mathrm{the}\mathrm{pump}\mathrm{plunger}}{\mathrm{Mechanical}\mathrm{advantage}} \\ =\frac{2}{8}=0.25\mathrm{kgf} \end{gathered}$$