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Standard IX

Mathematics

Properties of Parallelograms

The area of ...

Question

The area of $Δ A B C$ is $32 c m^{2}$ . $A D$ is median and $E$ is the midpoint jof $A D$ . Find the area of $Δ B E D$

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Solution

In the given figure,
We know that in $Δ A D B$ $B E$ is median hence,
$a r (Δ B E D) = a r (Δ A E B) = \frac{1}{2} a r (Δ A B D)$
$a r (Δ B E D) = \frac{1}{2} \times 16 c m^{2}$
$a r (Δ B E D) = 8 c m^{2}$
Hence,
We get $a r (Δ B E D) = 8 c m^{2}$ .

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In the given figure AD is median of $Δ A B C$ , DE is median of $Δ A B D$ and EF is median of $Δ B E D$ . If area of $Δ A B C$ is $128 c m^{2}$ , then area of $Δ B E F$ is

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The area of ΔABC is 32 cm2. AD is median and E is the midpoint jof AD. Find the area of ΔBED

In the given figure,We know that in ΔADB BE is median hence,ar(ΔBED)=ar(ΔAEB)=12ar(ΔABD)ar(ΔBED)=12×16cm2ar(ΔBED)=8cm2Hence,We get ar(ΔBED)=8cm2.

The area of $Δ A B C$ is $32 c m^{2}$ . $A D$ is median and $E$ is the midpoint jof $A D$ . Find the area of $Δ B E D$

In the given figure,
We know that in $Δ A D B$ $B E$ is median hence,
$a r (Δ B E D) = a r (Δ A E B) = \frac{1}{2} a r (Δ A B D)$
$a r (Δ B E D) = \frac{1}{2} \times 16 c m^{2}$
$a r (Δ B E D) = 8 c m^{2}$
Hence,
We get $a r (Δ B E D) = 8 c m^{2}$ .