The area of the base of a rectangular tank is 6500 $c m^{2}$ and the volume of water contained in it is 2.6 $m^{3}$ . The depth of water in the tank is

(a) 3.5 m (b) 4 m (c) 5 m (d) 8 m

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Solution

Given
l x b = 6500 $c m^{2} = 0.65 c m^{2}$
l x b x h = 2.6 $m^{3}$
0.65 x h = 2.6
h = $fraction numerator 2.6 over denominator 0.65 end fraction$
h = 4m

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The area of the base of a rectangular tank is 6500 cm2 and the volume of water contained in it is 2.6 m3. The depth of water in the tank is (a) 3.5 m (b) 4 m (c) 5 m (d) 8 m

Given l x b = 6500 cm2=0.65cm2 l x b x h = 2.6m3 0.65 x h = 2.6 h = h = 4m

The area of the base of a rectangular tank is 6500 $c m^{2}$ and the volume of water contained in it is 2.6 $m^{3}$ . The depth of water in the tank is

(a) 3.5 m (b) 4 m (c) 5 m (d) 8 m

Given
l x b = 6500 $c m^{2} = 0.65 c m^{2}$
l x b x h = 2.6 $m^{3}$
0.65 x h = 2.6
h = $fraction numerator 2.6 over denominator 0.65 end fraction$
h = 4m