Given: Rhombus with diagonals measuring 16cm and 12 cm.
To find: Area of the figure formed by lines joining the midpoints of the adjacent sides.
Calculation: We know that, ‘Area of a rhombus is half the product of their diagonals’.
H and F are the midpoints of AD and BC respectively.
Now ABCD is a parallelogram which means
From 1 and 2 we get that ABFH is a parallelogram.
Since Parallelogram FHAB and ΔFHE are on the base FH and between the same parallels HF and AB.
Adding 3 and 4 we get,
Hence the correct answer is option (b).