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Question

The area of the figure formed by joining the mid points of the adjacent sides of a thombus with diagonals 16 cm and 12 cm is
 


  1. 28cm2
     

  2. 48cm2
     

  3. 96cm2
     

  4. 24cm2
     


Solution

The correct option is B

48cm2
 


In rhombus ABCD,
P,Q,R and S are the mid points of sides AB, BC, CD and DA respectively and are joined in order to get a quad. PQRS.

Diagonals AC = 16 cm and BD = 12 cm
Area of PQRS=12 area rhombus ABCD
=12×AC×BD2=14×16×12cm2=48cm2
 

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