The area of the four walls of a room is $660$ $m^{2}$ and length is twice the breath the height being $11$ m. Find area of the ceiling.

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Solution

If the breadth is x, length is 2x
$∴$ $2 \times 11 \times (x + 2 x) = 660$
or $3 x = 660 \div 22 = 30$
or $x = 10$
Hence area of the ceiling
$= 2 x \times x = 2 x^{2}$
$= 2 \times 102 = 200 m^{2}$

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The area of the four walls of a room is 660 m2 and length is twice the breath the height being 11 m. Find area of the ceiling.

If the breadth is x, length is 2x∴ 2×11×(x+2x)=660or 3x=660÷22=30or x=10Hence area of the ceiling=2x×x=2x2=2×102=200m2

The area of the four walls of a room is $660$ $m^{2}$ and length is twice the breath the height being $11$ m. Find area of the ceiling.

If the breadth is x, length is 2x
$∴$ $2 \times 11 \times (x + 2 x) = 660$
or $3 x = 660 \div 22 = 30$
or $x = 10$
Hence area of the ceiling
$= 2 x \times x = 2 x^{2}$
$= 2 \times 102 = 200 m^{2}$