Question

The area of the given figure is ____ $c{m}^2$​. (Both the ends are semi-circular) (All dimensions in cm and $\pi$ = 22/7)

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Answer 1

Area of the two semi-circles = $\frac{1}{2}(\pi \times r^2)+\frac{1}{2}(\pi \times r^2)=\pi \times r^2=\frac{22}{7}\times 7\times 7=154c{m}^2$

Area of rectangular part = length $\times$ breadth = 10$\times$14 = 140 $c{m}^2$

Total area = Area of the two semi-circles + Area of the rectangle = 154 + 140 = 294 $c{m}^2$​