The area of the sector is $12$ $f t^{2}$ . Find the radius of the sector.

5

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5.53

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3.32

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4

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Solution

The correct option is B $5.53$ ft
Area of arc $= π r^{2} \times \frac{θ}{360}$
$π r^{2} \times \frac{45}{360} = 12$
$r = \sqrt{\frac{12 \times 8}{π}} = 5.53 f t$

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The area of the sector is 12 ft2. Find the radius of the sector.

The correct option is B 5.53 ftArea of arc=πr2×θ360πr2×45360=12r=√12×8π=5.53ft

The area of the sector is $12$ $f t^{2}$ . Find the radius of the sector.

The correct option is B $5.53$ ft
Area of arc $= π r^{2} \times \frac{θ}{360}$
$π r^{2} \times \frac{45}{360} = 12$
$r = \sqrt{\frac{12 \times 8}{π}} = 5.53 f t$