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Question

The armature of a dc motor has 15 Ω resistance. It draws a current of 1.6 A when run by 220 V dc supply. The value of back emf will be:

A
24 V
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B
196 V
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C
220 V
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D
244 V
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Solution

The correct option is B 196 V
Let back emf be V and emf of supply =V

Applying Kirchoff's loop law in the circuit:

V+VIR=0

V=(VIR)

Hence, Back emf=VIR

=2201.6×15

Back emf=196V

Answer-(B)

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