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Inductors in Circuits

The armature ...

Question

The armature of a dc motor has 20 $Ω$ resistance. It draws a current of 1.5 A when run by a 220 V dc supply. The value of the back emf induced in it is

A

150 V

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B

170 V

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C

180 V

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D

190 V

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Solution

The correct option is C 190 V
back emf = $220 - I \times R$ = $220 - 1.5 \times 20 = 190 V$

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