Question

Question 4

The ascending arrangement of $\frac{2}{3},\frac{6}{7},\frac{13}{21}$ is

Answer 1

Given $\frac{2}{3},\frac{6}{7},\frac{13}{21}$
LCM of $(3,7,21)=21$
$\therefore \frac{2}{3}=\frac{2}{3}\times \frac{7}{7}=\frac{14}{21}\frac{6}{7}=\frac{6}{7}\times \frac{3}{3}=\frac{18}{21}$
and $\frac{13}{21}=\frac{13}{21}$
Now compare $\frac{14}{21},\frac{18}{21}$ and $\frac{13}{21}$
So, $\frac{13}{21}<\frac{14}{21}<\frac{18}{21}$
Hence , $\frac{13}{21}<\frac{2}{3}<\frac{6}{7}$