The AsCl bond distance in AsCl3 is 2-20A- If radius of chlorine atom is 0-99A- then radius of As atom is-

The correct option is C 1.21 A^∘ AsCl bond length= 2.20∘ #160; A #160; Bond lengh =r^+ + r^ ,if radius of Cl atom = 0.99 ...

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Standard X

Chemistry

Covalent Bond

The AsCl bo...

Question

The $A s C l$ bond distance in $A s C l_{3}$ is $2.20 A^{\circ}$ . If radius of chlorine atom is $0.99 A^{\circ}$ , then radius of $A s$ atom is:

0.24 A^{\circ}

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3.19 A^{\circ}

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1.21 A^{\circ}

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2.09 A^{\circ}

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Solution

The correct option is C $1.21 A^{\circ}$
$A s C l$ bond length= $2.20 \circ A$
Bond lengh $= r^{+} + r^{-}$ ,
if radius of $C l$ atom = $0.99 \circ A$
Radius of $A s$ atom= $(2.20 - 0.99 \circ) A$
= $1.21 \circ A$

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The AsCl bond distance in AsCl3 is 2.20A∘. If radius of chlorine atom is 0.99A∘, then radius of As atom is:

The correct option is C 1.21A∘AsCl bond length= 2.20∘ABond lengh =r++r−,if radius of Cl atom = 0.99∘ARadius of As atom= (2.20−0.99∘)A = 1.21∘A

The $A s C l$ bond distance in $A s C l_{3}$ is $2.20 A^{\circ}$ . If radius of chlorine atom is $0.99 A^{\circ}$ , then radius of $A s$ atom is:

The correct option is C $1.21 A^{\circ}$
$A s C l$ bond length= $2.20 \circ A$
Bond lengh $= r^{+} + r^{-}$ ,
if radius of $C l$ atom = $0.99 \circ A$
Radius of $A s$ atom= $(2.20 - 0.99 \circ) A$
= $1.21 \circ A$