Question

The atomic mass of an element is $27$. If valency is $3$, the vapour density of the volatile chloride will be :

• A. 66.75
• B. 6.675
• C. 667.5
• D. 81

Answer 1

The correct option is A 66.75

As given that valency of metal is 3 and it is a chloride, than the compound should be $MC{l}_3$.

$V.D.$ = $\frac{Mw}{2}$

$Mol.wt.\left(Mw\right)$ = $27+3\times 35.5=133.5$

$\therefore V.D.=\frac{133.5}{2}=66.75$