The atomic mass of thorium is 232 and its atomic number is 90- During the course of its radioactive disintegration 6- and 4-particles are emitted- What is the atomic mass and atomic number of the final atom-

Decrease in mass due to emission of 6α particles =6× 4=24 .So, Atomic mass of the product atom =( 232 24 ) =208 Number of β particles emit ...

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Standard XII

Physics

Alpha Decay

The atomic ma...

Question

The atomic mass of thorium is $232$ and its atomic number is $90$ . During the course of its radioactive disintegration $6 α$ and $4 β$ -particles are emitted. What is the atomic mass and atomic number of the final atom?

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Solution

Decrease in mass due to emission of $6 α$ -particles $= 6 \times 4 = 24$ .
So, Atomic mass of the product atom $= (232 - 24) = 208$
Number of $β$ -particles emitted $= 2 \times$ Number of $α$ -particles $- (Z_{T h o r i u m} - Z_{F i n a l a t o m})$
$4 = 2 \times 6 - (90 - Z_{F i n a l a t o m})$
or $Z_{F i n a l a t o m} = 82$

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The atomic mass of thorium is 232 and its atomic number is 90. During the course of its radioactive disintegration 6α and 4β-particles are emitted. What is the atomic mass and atomic number of the final atom?

Decrease in mass due to emission of 6α-particles =6×4=24.So, Atomic mass of the product atom =(232−24)=208Number of β-particles emitted =2× Number of α-particles −(ZThorium−ZFinal atom)4=2×6−(90−ZFinal atom)or ZFinal atom=82

The atomic mass of thorium is $232$ and its atomic number is $90$ . During the course of its radioactive disintegration $6 α$ and $4 β$ -particles are emitted. What is the atomic mass and atomic number of the final atom?