Question

The atomic weight of Al is 27. When a current of 5 Faradays is passed through a solution of Al⁺³ions, the weight of Al deposited is

• A. 27 gm
• B. 36 gm
• C. 45 gm
• D. 39 gm

Answer 1

The correct option is C

45 gm

${Al}^{3+}+3e^{-}\to Al$
$E_{Al}=\frac{27}{3}=9$
$W_{Al}=E_{Al}\times No.offaradays=9\times 5=45gm$