The average age of 18 patients in a hospital ward was 71. One patient was discharged and a new patient got admitted and as a result the average became 69.5. What is the age of the new patient, if the age of the patient who was discharged is 73?

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Solution

The correct option is C 46
Initially the sum of ages of all inmates were $= 18 \times 71 = 1278$
Let the age of the patient who joined be = x
$\frac{1278 - 73 + x}{18} = 69.5$
So, x=(18\times 69.5)+73-1278=46

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The average age of 18 patients in a hospital ward was 71. One patient was discharged and a new patient got admitted and as a result the average became 69.5. What is the age of the new patient, if the age of the patient who was discharged is 73?

The correct option is C 46Initially the sum of ages of all inmates were =18×71=1278 Let the age of the patient who joined be = x 1278−73+x18=69.5 So, x=(18\times 69.5)+73-1278=46

The correct option is C 46
Initially the sum of ages of all inmates were $= 18 \times 71 = 1278$
Let the age of the patient who joined be = x
$\frac{1278 - 73 + x}{18} = 69.5$
So, x=(18\times 69.5)+73-1278=46