The average depth of Indian ocean is about 3000 m Bulk Modulus of water is 2-2- 104 N-m2 - g-10 m-s2-then the fractional compression is - VV of water at the bottom of Indian Ocean is-

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Standard XII

Chemistry

Charles' Law

The average d...

Question

The average depth of Indian ocean is about 3000 m Bulk Modulus of water is $2.2 \times 10^{4} N / m^{2}$ , $g = 10 m / s^{2}$ ,then the fractional compression is $\frac{Δ V}{V}$ of water at the bottom of Indian Ocean is:

13.6

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20.6

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12.6

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0.52

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Solution

The correct option is D $13.6$ %
Since Bulk modules = $\frac{s t r e s s}{s t r a i n} = \frac{s t r e s s}{\frac{Δ V}{V}}$

So $\frac{Δ V}{V} = \frac{s t r e s s}{B u l k m o d u l e s} = \frac{ϱ g h}{2.2 \times 10^{4}}$

= $\frac{1000 \times 10 \times 3000}{2.2 \times 10^{4}}$

$\frac{Δ V}{V} = 1363.63$

i.e. $\frac{Δ V}{V} \times 100 = 13.6$ %

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Similar questions

Q. The average depth of Indian Ocean is about

3000 m

. The fractional compression,

\frac{Δ V}{V}

of water at the bottom of the ocean is then
(Given: Bulk modulus of the water

= 2.2 \times 10^{9} N m^{- 2}

and

g = 10 m s^{- 2}

)

The average depth of Indian Ocean is about 3000 m. Calculate the fractional compression, $\frac{Δ V}{V}$ of water at the bottom of the ocean, given that the bulk modulus of water is $2.2 \times 10^{9} N m^{- 2}$ (consider $g = 10 m s^{- 2}$ )

Q. The average depth of Indian Ocean is about

3000 m

. The fractional compression,

\frac{Δ V}{V}

of water at the bottom of the ocean (given that the bulk modulus of the water =

2.2 \times 10^{9} {Nm}^{- 2} {and g=10 ms}^{- 2}

, assuming density of water remains constant) is

Q. The average depth of indian ocean is about 3000 m. The frictional compression,

\frac{Δ V}{V}

of work at the bottom of the ocean ( give that the bulk modulus of the water

2.2 \times 10^{9}

{N m}^{- 2}

and

g = 10 m s^{- 2}

Q. The average depth of Indian ocean is about

3000 m

. The value of fractional compression

\frac{Δ V}{V}

of water at the bottom of the ocean is:

[Given that the bulk modulus of water is

2.2 \times 10^{9} N m^{- 2}

g = 9.8 m s^{- 2}

and

ρ_{H_{2} O} = 1000 k g . m^{- 3}

]

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The average depth of Indian ocean is about 3000 m Bulk Modulus of water is 2.2×104 N/m2 ,g=10 m/s2,then the fractional compression is ΔVV of water at the bottom of Indian Ocean is:

The correct option is D 13.6 %Since Bulk modules = stressstrain=stressΔVVSo ΔVV=stressBulkmodules=ϱgh2.2×104 = 1000×10×30002.2×104 ΔVV=1363.63i.e. ΔVV×100=13.6%

The average depth of Indian ocean is about 3000 m Bulk Modulus of water is $2.2 \times 10^{4} N / m^{2}$ , $g = 10 m / s^{2}$ ,then the fractional compression is $\frac{Δ V}{V}$ of water at the bottom of Indian Ocean is: