Question

The average kinetic energy of an ideal gas per molecule in S.I. units at ${25}^{o}C$ is:

• A. $61\times 7\times {10}^{-21}$ $J$
• B. $6.17\times {10}^{-20}$ $J$
• C. $6.17\times {10}^{-21}$ $J$
• D. $7.16\times {10}^{-20}$ $J$

Answer 1

The correct option is C $6.17\times {10}^{-21}$ $J$

$K.E.(per$ $molecule)=\frac{3\times kT}{2}$

$K.E.=\frac{3\times 1.38\times {10}^{-23}\times 298}{2}=6.17\times {10}^{-21}$ $J$

The average kinetic energy of an ideal gas per molecule in S.I. units at ${25}^{o}C$ is $\frac{3}{2}kT$ which is $6.17\times 10$${}^{-21}$ $J$