Question

The average kinetic energy of an ideal gas per molecule in SI unit at ${25}^{\circ }C$ will be

• A. $6.17\times {10}^{-21}J$
• B. $6.17\times {10}^{-20}J$
• C. $6.17\times {10}^{-21}kJ$

Answer 1

The correct option is A $6.17\times {10}^{-21}J$

$KE=\frac{3RT}{2N_0}=\frac{3\times 8.3143\times 298}{2\times 6.023\times {10}^{23}}=6.17\times {10}^{-21}J$