Question

The average kinetic energy of an ideal gas per molecule in SI units at 25${}^{\circ }$C will be

• A. 6.17×10⁻²¹ kJ
• B. 6.17×10⁻²¹ J
• C. 6.17×10⁻²⁰ J
• D. 7.16×10⁻²⁰ J

Answer 1

The correct option is

A

The formula to calculate the average kinetic energy of an ideal gas is,

$AverageKE=\frac{3}{2}kT$

Boltzmann constant is given as $k$

The temperature is represented as T.

The value of Boltzmann constant is $1.38\times {10}^{-23}$ J/K

Average kinetic energy per molecule

$=\frac{3}{2}KT=\frac{3}{2}\times 1.38\times {10}^{-23}\times 300J=6.17\times {10}^{-21}J$