Question

The average kinetic energy of $H$-atom (or molecules) at room temperature of ${27}^{o}C$ is:

• A. 0.04 $eV$
• B. 0.4 $eV$
• C. 0.02 $eV$
• D. 0.2 $eV$

Answer 1

Answer: (A)

0.04 $eV$

As we know,
Average $KE$ $=\frac{3}{2}kT=\frac{3}{2}\times 1.38\times {10}^{-23}\times 300J$
$=\frac{3}{2}\times \frac{1.38\times {10}^{-23}\times 300}{1.6\times {10}^{-19}}=0.039eV$