Question

The average kinetic energy of the molecules of an ideal gas at ${10}^{\circ }C$ has the value E. The temperature at which the kinetic energy of the same gas becomes 2E is

• A. $5^{\circ }C$
• B. ${10}^{\circ }C$
• C. ${40}^{\circ }C$
• D. None of these

Answer 1

Answer: (D)

None of these

The average kinetic energy of gas molecules $T$

Thus $\frac{E_2}{E_1}=\frac{T_2}{T_1}=2$

$⟹T_2=2\times T_1$

$=2\times 283K=566K={293}^{\circ }C$