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Question

The average life of a W gm sample of 200Ra is T seconds and average energy of the β-particles emitted is E MeV. At what rate in watts does the sample emit energy?

A
8WN0ET×1016
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B
8(ln2)WN0ET×1013
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C
8WN0ET×1013
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D
None is correct
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Solution

The correct option is B 8WN0ET×1016
ET=No×Msample×EsampleT
Number of atoms =
NA×W200
=1021×6.023W200
=3.01W×1021N0 particles
=3.01W×1021N0T particles/sec \quad decay
Now energy released with a single β decay is 2.667×1037MeV and average energy released is E×103eV
ET=3.01W×1021N0×E×1037×2.667T
=8WN0E×1016T

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