The average oxidation states of sulphur in Na2S2O3 and Na2S4O6 are, respectively :
A
+5 and +2
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B
+2 and +2.5
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C
+5 and 2.5
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D
+2 and +4
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Solution
The correct option is B+2 and +2.5 Let x be the oxidation number of sulphur in Na2S2O3. For a neutral compound, sum of oxidation states of all elements must be zero. 2+2x+3(−2)=0 2x=6−2 2x=4 x=+2 Suppose y be the oxidation number of sulphur in Na2S4O6. 2+4y+3(−2)=0 4y=12−2 4y=10 y=+2.5 The average oxidation states of sulphur in Na2S2O3 and Na2S4O6 are respectively +2 and +2.5.