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Question

The average oxidation states of sulphur in Na2S2O3 and Na2S4O6 are, respectively :

A
+5 and +2
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B
+2 and +2.5
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C
+5 and 2.5
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D
+2 and +4
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Solution

The correct option is B +2 and +2.5
Let x be the oxidation number of sulphur in Na2S2O3.
For a neutral compound, sum of oxidation states of all elements must be zero.
2+2x+3(2)=0
2x=62
2x=4
x=+2
Suppose y be the oxidation number of sulphur in Na2S4O6.
2+4y+3(2)=0
4y=122
4y=10
y=+2.5
The average oxidation states of sulphur in Na2S2O3 and Na2S4O6 are respectively +2 and +2.5.

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