The average- S - F bond energy in SF6 if the - H-f value are -1100- -275 and -80 kJ-mol respectively for SF6g- Sg and Fg is

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Enthalpy

The average, ...

Question

The average, $S - F$ bond energy in $S F_{6}$ if the $Δ H_{f}^{\circ}$ value are $- 1100, + 275$ and $+ 80 k J / m o l$ respectively for $S F_{6} (g),$ S(g) and F(g) is

390.1 k J / m o l

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103.9 k J / m o l

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903.1 k J / m o l

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309.1 k J / m o l

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Solution

The correct option is D $309.1 k J / m o l$
As we know,
Heat of a reaction = Bond energy of reactants - Bond energy of products
here,
$S (s) + 3 F_{2} (g) \to S F_{6} (g)$
so heat of reaction =
$- 1100 = 275 + 6 * 80$ - bond energy of $S F_{6}$
bond energy of $S F_{6}$ $= 1855$
so bond energy of $S - F = 1855 / 6 = 309.1 k J / m o l$

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Similar questions

Q. The average

S - F

bond energy in

S F_{6}

if the

Δ H_{f}^{o}

values are

- 1100, + 275

and

+ 80

kJ/mol respectively for

S F_{6}

(g),

S

(g) and

F

(g) is:

The standard heat of formation values of $S F_{6} (g)$ , $S (g)$ and $F (g)$ are: $- 1100, 275$ and $80 K J m o l^{- 1}$ respectively. Then the average S - F bond energy in $S F_{6}$ is:

Q. The average S–F bond energy in

k J m o l^{- 1}

S F_{6}

is______. (Rounded off to the nearest integer)
[Given : The values of standard enthalpy of formation of

S F_{6} (g), S (g) and F (g) are 1100, 275 and 80 k J m o l^{- 1}

respectively.]

Q. The average

S - F

bond energy in

k J m o l^{- 1}

S F_{6}

is _____.(Rounded off to the nearest integer

[Given : The values of standard enthalpy of formation of

S F_{6} (g), S (g) a n d F (g)

are - 1100, 275 and 80 kJ

m o l^{- 1}

respectively]

The standard heat of formation values of $S F_{6} (g), S (g)$ and $F (g)$ are $- 1100, 275$ and $80$ J mol $^{- 1}$ respecitvely. The $S - F$ bond energy in $S F_{6}$ is :

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The average, S−F bond energy in SF6 if the ΔH∘f value are −1100,+275 and +80kJ/mol respectively for SF6(g), S(g) and F(g) is

The correct option is D 309.1kJ/molAs we know,Heat of a reaction = Bond energy of reactants - Bond energy of productshere,S(s)+3F2(g)→SF6(g)so heat of reaction = −1100=275+6∗80 - bond energy of SF6 bond energy of SF6 =1855so bond energy of S−F=1855/6=309.1kJ/mol

The average, $S - F$ bond energy in $S F_{6}$ if the $Δ H_{f}^{\circ}$ value are $- 1100, + 275$ and $+ 80 k J / m o l$ respectively for $S F_{6} (g),$ S(g) and F(g) is