The average speed of an object is defined to be

One half of the sum of the maximum and the minimum speeds

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Distance it travels multiplied by the time it takes

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The distance it travels divided by the time it takes

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

The speed determined over an infinitesimally small time interval

No worries! We‘ve got your back. Try BYJU‘S free classes today!

The value of the speed at the midpoint of the time interval

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B The distance it travels divided by the time it takes
The average speed of an object is defined as the distance traveled divided by the time
$v = \frac{D}{t}$

Where, $v$ = speed,
$D$ = distance and
$t$ = time

Suggest Corrections

Similar questions

Q. An auto travels for time 'T'. It travels with a uniform speed u in the first half and with a uniform speed of v in the second half of the given time interval. What will be the average speed of the train in the given time interval time 'T'?

Explain clearly, with examples, the distinction between:
a) magnitude of displacement (sometimes called distance) over an interval of time, and the total length of path covered by a particle over the same interval;
b) magnitude of average velocity over an interval of time, and the average speed over the same interval. [Average speed of a particle over an interval of time is defined as the total path length divided by the time interval]. Show in both (a) and (b) that the second quantity is either greater than or equal to the first.
When is the equality sign true? [For simplicity, consider one-dimensional motion only].

The value of speed calculated by $\frac{D i s t a n c e}{T i m e}$ gives us the average speed over the given time interval.