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Question

# The average translational energy and the rms speed of molecules in a sample of oxygen gas at 300 K are 6.21×10−21J and 484 m/s, respectively. The corresponding values at 600 K are nearly (assuming ideal gas behaviour).

A
12.42×1021J,968m/s
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B
8.78×1021J,684m/s
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C
6.21×1021J,968m/s
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D
12.42×1021J,684m/s
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Solution

## The correct option is D 12.42×10−21J,684m/sThe formula for average kinetic energy is¯¯¯¯¯¯¯¯¯¯¯¯¯(KE)=32KTtherefore¯¯¯¯¯¯¯¯¯¯¯¯¯(KE)600K¯¯¯¯¯¯¯¯¯¯¯¯¯(KE)300K=600300⇒¯¯¯¯¯¯¯¯¯¯¯¯¯(KE)600K=2×6.21×10−21J=12.42×10−21JAlso the formula for rms velocity isCrms=√3KTm∴(Crms)600K(Crms)300K=√600300⇒(Crms)600K=√2×484=684 m/s.

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