Question

The average velocity of a body moving with uniform acceleration travelling a distance $3.06\text{m}$ is $0.34\text{m/s}$. If the change in velocity of the body is $0.18\text{m/s}$ during this time, its uniform acceleration is

• A. $0.01{\text{m/s}}^2$
• B. $0.02{\text{m/s}}^2$
• C. $0.03{\text{m/s}}^2$
• D. $0.04{\text{m/s}}^2$

Answer 1

The correct option is B $0.02{\text{m/s}}^2$

Given, $v_{avg}=0.34\text{m/s}$
Change in velocity $=0.18\text{m/s}$
$\text{Total time taken}=\frac{\text{Distance}}{\text{Average Velocity}}=\frac{3.06}{0.34}=9\text{sec}$
And, $\text{acceleration}=\frac{\text{change in velocity}}{\text{time}}=\frac{0.18}{9}=0.02{\text{m/s}}^2$