Question

The axis of a hollow cone as shown in fig. is vertical. Its base radius is R. It is kept in a uniform electric field E parallel to its axis.

Answer 1

For A:

Area Perpendicular to E $=\pi R^2$

Hence Flux $=\pi R^2\times E$

Non Zero

Answer 1 & 4

For B:

Area Perpendicular to E $=\pi R^2$

Hence Flux $=\pi R^2\times E$

Non Zero

Answer 1 & 4

For C:

Area Perpendicular to E $=\frac{\pi R^2}{2}$

Hence Flux $=\frac{\pi R^2}{2}\times E$

Non Zero

Answer 2 & 4

For D:

Area Perpendicular to E $=\pi R^2$

Hence Flux $=\pi R^2\times E$

Flux coming out = Flux entering the surface of the cone

Zero

Answer 3