The balance equations for the reaction of zinc with sodium hydroxide solution :

Z n + 2 N a O H \to Z n (O H)_{2} + 2 N a

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Z n + N a O H \to N a Z n O_{2} + H_{2}

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Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}

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2 Z n + 2 N a O H \to 2 N a Z n O + H_{2}

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Solution

The correct option is C $Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$
Reactions:
$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$

Suggest Corrections

Similar questions

N a O H

100 %

I

2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}

2 H_{2} + O_{2} ⟶ 2 H_{2} O

I I

2 N a + \frac{1}{2} O_{2} ⟶ N a_{2} O

N a_{2} O + H_{2} O ⟶ 2 N a O H

2 N a O H (a q) + Z n (s) \to

2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}

H_{2}

0.46

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2 N a + 2 H_{2} O \to 2 N a O H + H_{2}

6 C O_{2} + 12 H_{2} O \to C_{6} H_{1} 2_{6} + 6 H_{2} O + 6 O_{2}

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