Question

The balanced equation for a reaction is given below
$2X+3Y\to \text{4I + m}$
When 8 moles of x react with 15 moles of y, then
i) Which is the limiting reagent?
ii) Calculate the amount of products formed.
iii) Calculate the amount of excess reactant left at the end of the reaction.

Answer 1

$2X+3Y\to 4I+m.$

$8$ mole of $x$ requires $\to \frac{3}{2}\times 8=12$ mole of $Y$

or $15$ moles of $Y$ requires $\to \frac{2}{3}\times 15=10$ moles of $X$

but only $8$ moles of $X$ are given so.

$\left(i\right)$. $X$ is limiting reagent (which decides product)

$\left(ii\right)$. $8$ moles of $X$ gives $16I$ and $4m$.

$\left(iii\right)$. $3$ moles of $Y$ remains unreacted.